Plimpton 322 and Babylonian Pythagorean Triples

A postcard-sized clay tablet from ancient Iraq, written about 1,200 years before Pythagoras, that lists right-triangle numbers in base 60. Here is how to read it row by row, and what scholars think it was for.

By the PythagoreanTheorem.net teamUpdated 12 min read

Plimpton 322 is a Babylonian clay tablet, written in cuneiform around 1800 BCE, whose 15 rows of base-60 numbers correspond to Pythagorean triples: whole-number sides of right triangles such as 119, 120 and 169. It is strong evidence that Babylonian scribes knew the relationship a2 + b2 = c2 more than a thousand years before Pythagoras.

Below you will learn to read its numbers yourself, see all fifteen rows as modern triples, and weigh the rival explanations of why it was made.

Plimpton 322 at a glance

What it isA clay tablet with a table of numbers in cuneiform script, four columns by fifteen rows
DateAbout 1800 BCE (Old Babylonian period), based mainly on its handwriting and format
Where it came fromProbably the city of Larsa in southern Iraq, according to the dealer who sold it
SizeAbout 13 cm wide, 9 cm tall and 2 cm thick; the left edge is broken off
Where it is nowColumbia University, New York. The publisher George A. Plimpton bought it from the dealer Edgar J. Banks in about 1922 and left his collection, in which it is number 322, to the university
Why it mattersThe oldest known list of Pythagorean triples

How to read Babylonian numbers

Babylonian scribes counted in base 60 (sexagesimal), pressing numbers into wet clay with a reed stylus. Two signs were enough: a vertical wedge worth 1 and a corner wedge worth 10, grouped to make any digit from 1 to 59. Digits are written in place value like ours, but each place is worth 60 times the next.

60s1s1,59 = 1 × 60 + 59 = 119= 1= 1060s1s2,49 = 2 × 60 + 49 = 169
Stylized cuneiform for the first row's two numbers. Each shaded box holds one base-60 digit: the left box counts sixties and the right box counts ones.

Modern scholars transliterate the digits with commas between places, so 1,59 means 1 × 60 + 59 = 119 and 2,49 means 2 × 60 + 49 = 169. A semicolon marks where the whole part ends and the fractional part begins:

1; 59, 00, 15 = 1 + 59 over 60 + 0 over 602 + 15 over 603 ≈ 1.9834028

There is a catch: Old Babylonian scribes wrote no semicolon and had no sign for zero. The same wedges could mean 119, or 1 + 59/60, or 7,140, and the reader judged the scale from context, as historians must on Plimpton 322.

Why base 60?Sixty divides evenly by 2, 3, 4, 5, 6, 10, 12, 15, 20 and 30, so many fractions come out exact. A number whose only prime factors are 2, 3 and 5 is called regular, and its reciprocal has a finite base-60 expansion. In base 10 only factors of 2 and 5 behave this way, which is why 1/3 never ends as a decimal but is simply 0;20 in base 60.

What the four columns say

Here are the first five rows in modern digits, one base-60 digit per group. The long side of each triangle is not on the tablet; you have to work it out.

I: (diagonal ÷ length)²heading partly brokenII: widthshort side sIII: diagonaldIV: line(1) 59 00 151 592 491(1) 56 56 58 14 56 1556 073 12 012(1) 55 07 41 15 33 451 16 411 50 493(1) 53 10 29 32 52 163 31 495 09 014(1) 48 54 01 401 051 375… rows 6–15 continue below
Our redrawing of rows 1–5 (not a photograph). The grey (1) at the start of column I sits on the damaged edge. Orange numbers are scribal errors: row 2 should read 50 06 15 at the end of column I and 1 20 25 in column III.
  • Column IV just numbers the lines, 1 to 15.
  • Column II has a heading that mentions the "width" and gives the short side s of a right triangle (or rectangle).
  • Column III has a heading that mentions the "diagonal" and gives the hypotenuse d.
  • Column I is a fraction between 1 and 2: the square of the diagonal divided by the square of the missing long side l.

Example: check row 1

Row 1 gives 1,59 = 119 and 2,49 = 169. If they are the legs and hypotenuse of a right triangle, the other leg must be √1692 − 1192:

l2= 1692 − 1192 = 28561 − 14161 = 14400l= √14400 = 120

Now column I: (169/120)2 = 28561/14400 = 1.98340277…, and that is exactly 1;59,00,15 in base 60.

Row 1 is the triple 119, 120, 169, and column I is d2/l2 written in base 60.

Because the edge is broken, some scholars drop the leading 1, which turns column I into s2/l2. The two readings differ by exactly 1, since d2/l2 − s2/l2 = 1 is just the Pythagorean theorem divided by l2. Eleanor Robson's reading of the damaged heading, roughly "the holding-square of the diagonal, from which 1 is torn out, so that the width comes up", describes exactly that step. Every implied long side (120, 3,456, 4,800 …) is a regular number, so column I always has a finite base-60 expansion.

All 15 rows of Plimpton 322

Here is every row as a modern triple, with the scribe's errors corrected. The long side l and the last two columns are our additions: p and q generate the row through Euclid's formula (s = p2 − q2, l = 2pq, d = p2 + q2), and the angle is opposite the short side, to the nearest hundredth of a degree.

RowShort side sLong side lDiagonal dd2/l2 (rounded)p/qAngle
11191201691.983402812/544.76°
23,3673,4564,8251.949158664/2744.25°
34,6014,8006,6491.918802175/3243.79°
412,70913,50018,5411.8862479125/5443.27°
56572971.81500779/442.08°
63193604811.785192920/941.54°
72,2912,7003,5411.719983754/2540.32°
87999601,2491.692709432/1539.77°
94816007691.642669425/1238.72°
104,9616,4808,1611.586122681/4037.44°
114560751.56252/136.87°
121,6792,4002,9291.489416848/2534.98°
131612402891.450017415/833.86°
141,7712,7003,2291.430238850/2733.26°
1556901061.38716059/531.89°

Column I falls steadily, so the triangles run from nearly isosceles (close to 45°) down to about 32°, in steps of roughly one degree. Row 11 is the 3-4-5 triangle scaled by 15 and row 15 is twice 28, 45, 53; every other row is a primitive triple. Nobody finds 12,709, 13,500, 18,541 by trial and error, so the scribe had a method. In 1964 Derek de Solla Price noticed that there are exactly fifteen pairs of regular numbers p and q with no common factor, q below 60 and p/q between 9/5 and 12/5, and sorted by size they give the tablet's rows in order.

The scribe's six mistakes

Most scholars count six errors, which are useful clues to how the numbers were computed:

  • Row 2, column I: the digits 50 06 are run together as 56.
  • Row 2, column III: 3 12 01 instead of 1 20 25 (4,825), not explained by any single slip.
  • Row 8, column I: the two digits 45 14 are replaced by their sum, 59.
  • Row 9, column II: 9 01 (541) is written for 8 01 (481).
  • Row 13, column II: 7 12 01 (25,921) for 2 41 (161). Since 1612 = 25921, the scribe copied the square, not its root.
  • Row 15: 56 and 53 do not belong together. Either 53 should be 1 46 (106) or 56 should be 28.

What was Plimpton 322 for?

Nobody knows for certain. The four main interpretations answer two separate questions: how the numbers were calculated, and why anyone wanted them.

1. Number theory (Neugebauer and Sachs, 1945)

Otto Neugebauer and Abraham Sachs, who first published the tablet's mathematics in 1945, suggested the scribe chose regular numbers p and q and computed the sides with a rule like Euclid's formula, as a study of whole-number solutions of s2 + l2 = d2. Critics such as R. Creighton Buck and Eleanor Robson reply that this leaves column I, the order of the rows and the errors unexplained, and that pure number theory looks out of place among the practical problem texts of the period.

2. Reciprocal pairs and cut-and-paste geometry

The explanation favored by many specialists today starts from a single number x and its reciprocal 1/x, the kind of pair listed in the reciprocal tables that every scribe learned. The idea goes back to Evert Bruins in 1949 and was developed by Jöran Friberg and Eleanor Robson, among others. From the pair you compute

x − 1/x over 2 and x + 1/x over 2,

which are the short side and diagonal of a right triangle whose long side is 1. For row 1, x = 2; 24 = 12/5 and 1/x = 0; 25 = 5/12:

12/5 − 5/12 over 2 = 119 over 120  12/5 + 5/12 over 2 = 169 over 120

Scale up by 120 to clear the fractions and you have 119, 120 and 169. The geometry behind it is the Babylonian "cut-and-paste" method for completing the square, which appears in other problem texts of the same period.

rectangle x × 1/x: sides 12/5 and 5/12, area 1(x + 1/x)/2 = 169/120(x − 1/x)/2= 119/120Move half the excess:big square − small square= the rectangle’s area = 1(169/120)² − (119/120)² = 1Multiply by 120²:169² − 119² = 120²Row 1: 119, 169 (and 120)
A rectangle of sides x and 1/x has area 1. Cut off half the excess length and move it to the top: the result is a big square with a small square missing, so the big square minus the small square equals 1.

This reading explains column I (the big square: 1 plus the small square), the order of the rows (decreasing x), the headings and several of the errors. Two other Old Babylonian tablets, MS 3052 and MS 3971 in the Schøyen Collection, compute a rectangle's width and diagonal starting from a reciprocal pair, which strongly supports the idea.

3. A teacher's list (Robson, 2001–2002)

Robson also asked who would make such a table. The tablet's format matches administrative documents from Larsa, so she argued that its author was a trained scribe and that the table was most likely a teacher's list of numbers for setting right-triangle problems with exact answers. Her 2002 article on it won the Mathematical Association of America's Lester R. Ford Award.

4. A trigonometric table (Mansfield and Wildberger, 2017)

Neugebauer and Sachs had noticed that column I is the square of a trigonometric ratio (the secant, or the tangent without the leading 1; the two readings differ by the Pythagorean identity sec2θ = 1 + tan2θ). In 2017 Daniel Mansfield and Norman Wildberger argued in Historia Mathematica that the tablet is "exact sexagesimal trigonometry", a table of exact side ratios built without angles, and the publicity around the paper called it superior in some ways to modern trigonometry.

Historians were skeptical. The trigonometric observation was decades old; there is no evidence that Old Babylonian scribes measured angles at all; a tablet with six errors can hardly be "completely accurate", as the publicity claimed; and the reciprocal-pair method already explains the numbers with techniques attested elsewhere. Robson had earlier called the trigonometric reading "conceptually anachronistic", and the writer Evelyn Lamb summed up the objections in Scientific American. Trigonometry is a fair modern way to describe the numbers, as the angle column shows, but probably not how the scribe thought of them.

Where things stand

Key ideaScholars agree on what the tablet says and that its author understood the Pythagorean relationship. The reciprocal-pair method is the best-supported account of how the numbers were produced. Why the table was made is still open, with the teaching-aid explanation the most widely held.

YBC 7289: the square root of 2 tablet

YBC 7289, in the Yale Babylonian Collection, is a small round school tablet from roughly 1800–1600 BCE. It shows a square with both diagonals; one side is labeled 30, and two numbers run along a diagonal.

301 24 51 1042 25 35Diagonal ÷ side ≈ √21;24,51,10 = 1 + 24/60+ 51/3600 + 10/216000≈ 1.4142130true √2 ≈ 1.414213630 × 1;24,51,10 = 42;25,35≈ 42.4264, the diagonalof a square with side 30
Our redrawing of YBC 7289 in modern digits. The tablet is often photographed turned 45°; Babylonian convention probably had the labeled side at the top, as here.

The first number is the ratio of a square's diagonal to its side, which by the theorem is √2 for any square (a square is two 45-45-90 triangles):

1; 24, 51, 10 = 1 + 24 over 60 + 51 over 602 + 10 over 603 = 305470 over 216000 ≈ 1.4142130

The true value is √2 ≈ 1.4142136, so the scribe is too small by about 0.0000006, roughly one part in 2.4 million. The second number, 42;25,35, is 30 times the first: the diagonal of a square with side 30, about 42.4264. Since place value is not marked, the side could also mean 30/60 = 1/2, making the second number 0; 42, 25, 35 ≈ 0.70711 ≈ 1/√2. Either way, the scribe was applying the diagonal rule, and the same value was still in use in Ptolemy's Almagest almost two thousand years later. No fraction can be exactly right, because √2 is irrational.

What the tablet tells us about the theorem's history

Plimpton 322 contains no proof and states no general rule. But fifteen exact triples with five-digit sides, produced by a consistent method, are hard to explain unless the author knew that the square on the diagonal equals the squares on the two sides. Other tablets agree: IM 67118, excavated in 1962 near Baghdad, finds the sides of a rectangle from its area and diagonal, then checks the answer with the rule. So historians date the theorem to at least the Old Babylonian period, about 1,200 years before Pythagoras. The wider story, including India, China and Egypt's much weaker evidence, is on the history of the Pythagorean theorem page and the Egyptian rope stretchers page.

Frequently asked questions

What is Plimpton 322?

An Old Babylonian clay tablet with a four-column table of base-60 numbers. Two columns give the short side and diagonal of fifteen right triangles with whole-number sides, one gives a related ratio, and one numbers the rows. It is the oldest known list of Pythagorean triples.

How old is Plimpton 322?

It is usually dated to about 1800 BCE from its handwriting and its resemblance to other tablets from Larsa. That makes it roughly 3,800 years old.

Does Plimpton 322 prove the Babylonians knew the Pythagorean theorem?

It shows that they knew the relationship and had a reliable method for producing exact triples. It is not a proof in the Greek sense: no Babylonian text explains why the rule is true.

Is Plimpton 322 a trigonometry table?

Its first column can be described with trigonometric ratios, and in 2017 two mathematicians argued that it is exact trigonometry. Most historians disagree: there is no evidence that Old Babylonian scribes measured angles, and reciprocal pairs explain the numbers well.

Where is Plimpton 322 kept?

At Columbia University in New York, in the collection that the publisher George A. Plimpton left to the university in the mid-1930s.

Sources and further reading

  1. O. Neugebauer and A. Sachs, Mathematical Cuneiform Texts (American Oriental Society, New Haven, 1945), pp. 38–41.
  2. R. Creighton Buck, "Sherlock Holmes in Babylon", The American Mathematical Monthly 87 (1980): 335–345.
  3. Eleanor Robson, "Neither Sherlock Holmes nor Babylon: a reassessment of Plimpton 322", Historia Mathematica 28 (2001): 167–206.
  4. Eleanor Robson, "Words and pictures: new light on Plimpton 322", The American Mathematical Monthly 109 (2002): 105–120.
  5. Eleanor Robson, Mathematics in Ancient Iraq: A Social History (Princeton University Press, 2008).
  6. John P. Britton, Christine Proust and Steve Shnider, "Plimpton 322: a review and a different perspective", Archive for History of Exact Sciences 65 (2011): 519–566.
  7. Daniel F. Mansfield and N. J. Wildberger, "Plimpton 322 is Babylonian exact sexagesimal trigonometry", Historia Mathematica 44 (2017): 395–419.
  8. Evelyn Lamb, "Don't Fall for Babylonian Trigonometry Hype", Scientific American blog, August 29, 2017.
  9. David Fowler and Eleanor Robson, "Square root approximations in Old Babylonian mathematics: YBC 7289 in context", Historia Mathematica 25 (1998): 366–378.
  10. Wikipedia, "Plimpton 322", with the full transliteration (a secondary pointer).

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